Dust falls on a certain metropolitan area at a rate of 67 mg·m−2·day−1. Major metallic elements in the dust include Al, Mg, Cu, Zn, Mn, and Pb. Mn accumulates at a rate of 0.06 mg·m−2·day−1. How many metric tons (1 metric ton = 1000 kg) of Mn fall on the 556 square kilometers of this metropolitan area in 5.0 years?

60.9 metric tons of Mn are accumulated

Explanation:

The Mn accumulates at a rate of 0.06 mgm⁻²day⁻¹.

After 5.0years (5years * 365 = 1825days) will be accumulate:

0.06 mgm⁻²day⁻¹ * 1825 days =

109.5mgm⁻²

Now, 556km² are:

556 km² * ((1000m)² / 1km) = 5.56x10⁸ m²

In 5.56x10⁸ m² you will accumulate:

5.56x10⁸ m² * 109.5mgm⁻² = 6.09x10¹⁰mg are accumulated.

In kg:

6.09x10¹⁰mg * (1kg / 1x10⁶mg) = 6.09x10⁴kg.

In metric tons:

6.09x10⁴kg * (1 metric ton / 1000kg) =

answer: mercury

explanation:

in 1783 cavendish was working with his hydrogen gas and found that when he burned it and condensed the vapor it was water. this was very significant since it disproved the greek theory of elements completely since water was not a simple substance but the product of two gases. it was lavoisier who hearing of the experiment gave cavendish's gas the name hydrogen ("water-producer") and added that hydrogen burned by combining with oxygen and that water was a hydrogen-oxygen combination.

explanation: