PLEASE HELP M ASAP If a 28.5 g piece of copper is added to a graduated cylinder containing 45.5 mL of water and the water level rose to 49.1 mL, what is the density of the copper?

Approx

8

⋅

g

⋅

m

L

−

1

Explanation:

ρ

,

density

=

Mass

Volume

=

28.5

⋅

g

(

49.10

−

45.50

)

⋅

m

L

=

7.92

⋅

g

⋅

m

L

−

1

Explanation:

so here we go

atomic mass

239 + 1 = y + 134 + 3 combine like terms

240 = y + 137             subtract 137 from both terms

240 - 137 = y

103 = y

atomic number

94 = z +54 + 0

94 = z + 54               subtract 54 from both sides.

40 = z

answer