6 X, Y and Z are all gases that behave ideally and react according to the equation shown.
X(g) + 2Y(g) → 2Z(9)
When 3.0 mol of X and 3.0 mol of Y are placed inside a container with a volume of 1.0 dmº, they
react to form the maximum amount of Z.
The final temperature of the reaction vessel is 120°C.
What is the final pressure inside the reaction vessel?
А
4.49 x 10 Pa
B
9.80 x 106 Pa
C
1.47 x 10' Pa
D
1.96 x 10' Pa

D

Explanation:

PV=nRT

n=nx + my

n=3mol+3mol

n=6mol

T=120+273=393K

P=nRT/V

P=6×0.0821×393/1

P=193atm

1atm=1.01325×10^5Pa

193atm=xPa

x=1.96×10^7Pa

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole