What is the average atomic mass 'AAM of (BI) Blairium? Only type in the numerical answer, not the units (amu)! Please help give the work in how to figure it out! I will give you brainiest! This is due in a few minutes and i’m struggling :(

47.42 amu.

Explanation:

The following data were obtained from the question:

Isotope A (Bl–47)

Mass number = 46.91 amu

Abundance = 53.4%

Isotope B (Bl–48):

Mass number = 47.98 amu

Abundance = 46%

Isotope C (Bl–50)

Mass number = 50.12 amu

Abundance = 100 – (53.4 + 46)

Abundance = 100 – 99.4

Abundance = 0.6%

Average atomic mass of Blairium =?

The average atomic mass can be obtained as follow:

Average atomic mass = [(mass of A × A%)/100] + [(mass of B × B%)/100] + [(mass of C × C%)/100]

Average atomic mass = [(46.91 × 53.4)/100] + [(47.98 × 46)/100] + [(50.12 × 0.6)/100]

Average atomic mass = 25.05 + 22.07 + 0.3

Average atomic mass = 47.42

Therefore, the average atomic mass of blairium is 47.42 amu.

the correct option is c.

isotopes refers to different forms of the same element with the same atomic number but different mass number as a result of difference in their neutron numbers. isotopes have different relative atomic mass but share the same chemical properties.