Hydrogen gas P1=15 psia, T1= 80 degree F. Compressed at a rate of 20 ft3/min in a hot environment until P2= 75.3 psig. Heat is introduced at a rate of 20 BTU/min and the change in entropy is 0.268 BTU/min-R. T1= 540R, H1= 3660.9, U1=2588.5, Sp. Heat = 31.232

(a) What is final T in R?

(b) What is the work equivalent Hp if the system is non flow?

(c) Work if the system is steady flow in btu/min?

it means there are 3 atoms of oxygen

give me abc and i will get it for u.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied