Suppose a mercury thermometer contains 3.250g of mercury and has a capillary that is 0.180mm in diameter.. how far does the mercury rise in the capillary when the temperature changes from 0.0 ∘c to 25.0 ∘c? the density of mercury at these temperatures is 13.596 g/cm3 and 13.534 g/cm3, respectively.

The steps in solving this problem are the following:

1. Sort the given from the problem.

2. Get the volume of mercury at 0.0 °C and 25.0 °C.

3. Get the difference in volume for the two temperatures.

4. Solve for the height of the mercury using the volume of a cylinder (shape of the thermometer).

STEP 1. Sort the given information in the problem.

Given:

mass of mercury = 3.250 g

diameter of capillary = 0.180 mm

density at 0.0°C = 13.596 g/cm³

density at 25.0° = 13.534 g/cm³

Find:

volume change from 0.0°C to 25.0° C

change in height from 0.0°C to 25.0°C

STEP 2: Using the equation for density, calculate the volume at 0.0°C and 25.0° C. The general equation to be used is:

For 0.0°C

For 25.0°C

STEP 3: Solve for the volume change.

STEP 4: From the change in volume, the change in height can be calculated using the equation below:

From the given in the problem, the least number of significant figures is 2, thus, the final answer must only have 2 significant figures as well.

Therefore,

Keywords: mercury thermometer

it is b that is the answer.