How much energy will a photon with a frequency of 6.8 x 104 Hz emit?

Energy emitted by photon = 45.06 × 10−32 J

Explanation:

Energy of photon is given by  E = hf

where

h is the Planck's constant whose value is 6.626×10−34J⋅s

f is the frequency of photon

given that

f = 6.8 x 104 Hz

1 HZ = 1 s^-1

E =  6.626×10−34J⋅s * 6.8 x 10^4 Hz

E = 45.06 × 10−32 J

Thus,

Energy emitted by photon is 45.06 × 10−32 J

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

pie chart because it is in percents ( % )