How many mililiters of a 6 00 M NaOH solution are needed to provide 0 330 mol of NaOH?

55mL of sodium hydroxide are required.

Explanation:

Given data:

Molarity of NaOH solution = 6.00 M

Number of moles of NaOH = 0.330

Volume required = ?

Solution:

Formula:

M = n/v

M = molarity

n = number of moles

v = volume

Now we will put the values in formula.

6.00 M = 0.330 mol / v

v = 0.330 mol / 6.00 M

v = 0.055 L  (M = mol/L)

v = 0.055 L × 1000 mL/ 1L

v = 55 mL

55mL of sodium hydroxide are required.

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