PLEASE HELP ME ASAP if you do this can you please show your work

3.83%

Explanation:

First, find the average of the measured value.  You should get 286.

291 + 287 + 295 + 281 = 1154

1154/4 = 288.5

Subtract the accepted value (300) from the average measured value (286).  Take the absolute value of your answer.  You should get 14.

288.5 - 300 = -11.5 = 11.5

Divide the difference from the above problem (14) by the accepted value (300).  You should get 0.0467.

11.5/300 = 0.0383

Multiply by 100%.

0.0383 × 100% = 3.83%

The percent error is 3.83%.

3.83 percent

Explanation:

Accepted Value = 300 degrees celsius

So since we are given the formula for percentage error,

we know that we have to find the average measured value since the accepted value is already provided

Average Measured Value:

Sum of all measured values / number of measured values

(291 + 287 + 295 + 281) / 4

1154 / 4

288.5 degrees celsius

Now, plugging the values in the given formula:

(average measured value - accepted value) *100 / accepted value

(288.5 - 300) * 100 / 300

-1150 / 300

-3.83 percent

Taking Absolute Value:

3.83 percent

Hence, the average value of the temperature is 3.83 percent less than the accepted value

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

wher is the rest of the question