This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water.

Complete Question:

This diagram shows a marble with a mass of 3.8 grams (g) that was placed into 10 milliliters (mL) of water. Using the formula V M D = , what is the density of the marble?

(See attachment for full diagram)

1.27 g/cm³

Explanation:

First, find the volume of rock:

Volume of rock = volume of water after rock was placed - volume of water before rock was placed

Volume of rock = 13 - 10 = 3ml

Density of rock = grams of rock per 1 cm³

Note: 1 ml = 1 cm³

Let x represent amount of rock per 1 cm³

Thus,

3.8g = 3 cm³

x = 1 cm³

Cross multiply

1*3.8 = 3*x

3.8 = 3x

3.8/3 = 3x/3

1.27 = x

Density of rock = 1.27 g/cm³

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it forms an anion that has a larger radius. anions have a negative charge and are larger than the original atom.