How many grams are in 0.005 moles of lead (IV) sulfate, Pb(SO­4)2 Group of answer choices 1.5 g 502.74 g 0.0045 g 1.996 g

Explanation:

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In this case, given the formula of the lead (IV) sulfate, we can compute its molar mass as shown below:

Thus, by applying the following mole-mass relationship, we obtain the mass of 0.005 moles of lead (IV) sulfate:

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