Calcular el módulo de elasticidad de un resorte, al cual se le aplica un esfuerzo cuya magnitud es de 7 x 10exponente a la 7 y se deforma 0.4 m. con el procedimiento completo y el análisis dimensional.
por favor me urge amigos :(

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

it takes on an electronical energy

idk what is it? is this a question that you know the answer or u dont