hydrogen peroxide slowly decomposes into water and oxygen. the enthalpy change of reaction can be calculated using standard enthalpies of formation. Using a Hess cycle what is the enthalpy change of reaction for this decomposition

a: 45.9 meters

b: 4.29 seconds

step-by-step explanation:

a: h(t)=1/2(-9.8)(3)^2+0(3)+90

h(t)=-4.9(3)^2+90

h(t)=-44.1+90

h(t)=45.9 meters

b: 0=1/2(-9.8)(t^2)+0t+90

0=-4.9t^2+90

-90=-4.9t^2

18.37=t^2

t=4.29 seconds

in the second question, the numbers aren't exact, but they're a close approximation.

the answer is the first option

explanation:

just googled it m8. not that hard

lol

2b2t

explanation:

2b2t