In the Deacon process for the manufacture of chlorine, HCl and O2 react to form Cl2 and H2O. Sufficient air (21.0 mole % O2, 79.0% N2) is fed to provide 35.0% excess oxygen and the fractional conversion of HCl is 75.0%. a. Calculate the mole fractions of the product stream components using atomic species balances in your calculation. N2 O2 Cl2 HCl H2O b. Again calculate the mole fractions of the product stream components using the extent of reaction and stoichiometric coefficients in the calculation for the conditions of 40.0% excess oxygen and a fractional conversion of HCl of 80.0%. N2

answer; i believe that the correct answer is (c) explore the outer planets; / plz check good luck

3 1/4 %

explanation:

i don,t know so just answer mine

c is having 4 valence electrons and is bonded to three hydrogens and one sulphur atom, therefore, the number of bond pair is equal to four. as all the valence electrons are used in forming the bonds so, there is no lone pair left on carbon.

s is having 6 valence electrons and is bonded to one other sulfur atom and one carbon atom, therefore, the number of bond pair is equal to 2. as only two valence electrons are used in forming the bonds so, four electrons are left. therefore, two lone pairs are present on s.