How many moles are present in 4.50 L of fluorine gas (F2) at Standard Temperature and
Pressure?

4.50 L gas of fluorine at STP contain 0.2 moles.

Explanation:

Given data:

Volume of gas = 4.50 L

Number of moles F₂ gas  = ?

Temperature of gas = standard =  273.15 K

Pressure of gas = standard = 1  atm

Explanation:

Formula:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will put the values in formula.

1 atm × 4.50 L = n × 0.0821 atm.L/ mol.K  × 273.15 K

4.50 atm.L  = n × 22.43 atm.L/ mol.

n = 4.50 atm.L   / 22.43 atm.L/ mol.

n = 0.2 mol

4.50 L gas of fluorine at STP contain 0.2 moles.

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.