The conjugation of the trans/cis product is likely diminished due to steric interactions between the cis-phenyl and the nearby vinyl hydrogen. This interaction likely causes the phenyl ring to twist out of the plane, and thus no longer to be fully conjugated with the adjacent double bond. The trans-trans isomer has no such steric interactions, and thus it is expected to be more fully conjugated. The two isomers are thus may have different light absorbing properties. Considering all this, which product stereoisomer do you expect to have the highest lambda max value in the UV-V is spectrum- the trans/trans or the cis/trans? Briefly explain your answer.

The trans/trans stereoisomer.

Explanation:

So, we are going to have two stereoisomers or arrangements for this chemical compound, that is the Cis/trans, the trans/trans.

For a compound to be seen with UV, the main or primary condition is conjugation or how conjugated the chemical specie or compound is.

Thus, the more the conjugation, the more or the higher the wavelength or lands value.

=> The Trans/trans stereoisomer will have the highest lamda value or wavelength because the energy gap in its π - π* Transitioning deceases due to the STERIC interactions, and the more the decrease in the energy gap, the more or the higher the lamda value or wavelength.

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explanation:

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the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.