How many ions are present in 30.0ml of 0.600m na2co3 solution?

 are present in 30 mL of 0.600 M  solution.

Further Explanation:

The proportion of substance in the mixture is called concentration. The most commonly used concentration terms are as follows:

1. Molarity (M)

2. Molality (m)

3. Mole fraction (X)

4. Parts per million (ppm)

5. Mass percent ((w/w) %)

6. Volume percent ((v/v) %)

Molarity is a concentration term that is defined as the number of moles of solute dissolved in one litre of the solution. It is denoted by M and its unit is mol/L.

The formula to calculate the molarity of ] solution is as follows:

      …… (1)

Rearrange equation (1) to calculate the moles of  solution.

                                         …… (2)

The molarity of  solution is 0.600 M.

The volume of  solution is 30 mL.

Substitute these values in equation (2).

The dissociation of  occurs as follows:

This indicates that one mole of  dissociates to form two moles of  ions and one mole of   ion. So total of three moles of ions are produced by one mole of .

The total number of moles of ions produced during the reaction is calculated as follows:

The formula to calculate the number of ions is as follows:

                        …… (3)

The number of moles of ions is 0.054 mol.

The value of Avogadro’s number is .

Substitute these values in equation (3).

Learn more:

1. The mass of ethylene glycol: link

2. Calculate the moles of ions in HCl solution: link

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Concentration terms

Keywords: molarity, ions, moles, Na2CO3, Na+, CO32-, 2Na+, 0.018 mol, 0.054 mol, Avogadro’s number, 3.25*10^22 ions, volume of Na2CO3, moles of Na2CO3.

b) mutualism

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