Chemistry, 29.09.2019 09:00 charae0185

The kp for the reaction below is 1.49 × 108 at 100.0°c: co(g) + cl2(g) → cocl2(g) in an equilibrium mixture of the three gases, pco = pcl2 = 2.22 × 10-4 atm. the partial pressure of the product, phosgene (cocl2), is atm.

Answers: 1

Show answers

Answers

Answer from: missbecca1229p6glel

7.34 atm

Further explanation

Given:

The Kp for the reaction below is 1.49 · 10⁸ at 100.0°C $\boxed{ \ CO_{(g)} + Cl_2_{(g)} \rightleftharpoons COCl_2_{(g)} \ }$ (a balanced reaction)

In an equilibrium mixture of the three gases.

p CO = p Cl₂ = 2.22 · 10⁻⁴ atm.

Question:

The partial pressure of the product, phosgene (COCl₂), is __ atm.

The Process:

Let us write the equilibrium constant in terms of pressure based on the reaction above.

$\boxed{ \ K_p = \frac{(p_{(products)})^{coefficient}}{(p_{(reactants)})^{coefficient}} \ }$ $\rightarrow \boxed{ \ K_p = \frac{p COCl_2}{(p CO)(p Cl_2)} \ }$

We set p COCl₂ as the subject to be asked.

$\boxed{ \ p COCl_2 = K_p{(p CO)(p Cl_2)} \ }$

Substitute all the data above into the equation.

$\boxed{ \ p COCl_2 = 1.49 \cdot 10^8 \times 2.22 \cdot 10^{-4} \times 2.22 \cdot 10^{-4} \ }$

Thus, the partial pressure of the product, phosgene (COCl₂), is 7.34 atm.

_ _ _ _ _ _ _ _ _ _

Notes:

For the general reactions: $\boxed{ \ aA + bB \rightleftharpoons cC + dD \ }$ ,

the equilibrium constant in terms of concentrations is given by the expression:

$\boxed{ \ K_c = \frac{[C]^c[D^d]}{[A]^a[B]^b} \ }$

Learn moreWrite the equilibrium constant for the reaction Write the equilibrium constant for the reaction of a heterogeneous balance. What is [S²⁻] at equilibrium?
The kp for the reaction below is 1.49 × 108 at 100.0°c: co(g) + cl2(g) → cocl2(g) in an equilibrium

The kp for the reaction below is 1.49 × 108 at 100.0°c: co(g) + cl2(g) → cocl2(g) in an equilibrium

Answer from: nan487

The partial pressure of phosgene $\left( {{\text{COC}}{{\text{l}}_2}} \right)$ is $\boxed{7.343316{\text{ atm}}}$ .

Further explanation:

Chemical equilibrium:

The state where reactant concentration and product concentration become constant and do not change with time is known as equilibrium.The rate of forward and backward reactions becomes equal at equilibrium.

Equilibrium constant in pressure terms:

The ratio of partial pressures of products to partial pressures of reactants, both of these terms are raised to some power equal to their respective coefficients in a balanced chemical equation. It is denoted by ${{\text{K}}_{\text{p}}}$ .

Consider a general balanced reaction,

${\text{aA}}\left( g \right) + {\text{bB}}\left( g \right) \rightleftharpoons {\text{cC}}\left( g \right) + {\text{dD}}\left( g \right)$

The formula to calculate ${{\text{K}}_{\text{p}}}$ is as follows:

${{\text{K}}_{\text{p}}} = \dfrac{{{{\left[ {{{\text{P}}_{\text{C}}}} \right]}^{\text{c}}}{{\left[ {{{\text{P}}_{\text{D}}}} \right]}^{\text{d}}}}}{{{{\left[ {{{\text{P}}_{\text{A}}}} \right]}^{\text{a}}}{{\left[ {{{\text{P}}_{\text{B}}}} \right]}^{\text{b}}}}}$

Here,

${{\text{P}}_{\text{C}}}$ and ${{\text{P}}_{\text{D}}}$ are partial pressures of C and D respectively.

${{\text{P}}_{\text{A}}}$ and ${{\text{P}}_{\text{B}}}$ are partial pressures of A and B respectively.

a and b are stoichiometric coefficients of A and B respectively.

c and d are stoichiometric coefficients of C and D respectively.

Given reaction is as follows:

${\text{CO}}\left( {\text{g}} \right) + {\text{C}}{{\text{l}}_2}\left( {\text{g}} \right) \rightleftharpoons {\text{COC}}{{\text{l}}_{\text{2}}}\left( {\text{g}} \right)$

The expression for equilibrium constant for this reaction is as follows:

${{\text{K}}_{\text{p}}} = \dfrac{{{{\text{P}}_{{\text{COC}}{{\text{l}}_2}}}}}{{{{\text{P}}_{{\text{CO}}}}{{\text{P}}_{{\text{C}}{{\text{l}}_2}}}}}$ ...... (1)

Where,

${{\text{K}}_{\text{p}}}$ is equilibrium constant.

${{\text{P}}_{{\text{COC}}{{\text{l}}_{\text{2}}}}}$ is partial pressure of ${\text{COC}}{{\text{l}}_{\text{2}}}$ .

${{\text{P}}_{{\text{CO}}}}$ is partial pressure of CO.

${{\text{P}}_{{\text{C}}{{\text{l}}_{\text{2}}}}}$ is partial pressure of ${\text{C}}{{\text{l}}_2}$ .

Rearrange equation (1) to calculate ${{\text{P}}_{{\text{COC}}{{\text{l}}_{\text{2}}}}}$ .

${{\text{P}}_{{\text{COC}}{{\text{l}}_2}}} = {{\text{K}}_{\text{p}}}{{\text{P}}_{{\text{CO}}}}{{\text{P}}_{{\text{C}}{{\text{l}}_2}}}$ …… (2)

Substitute $1.49 \times {10^8}$ for ${{\text{K}}_{\text{p}}}$ , $2.22 \times {10^{ - 4}}{\text{ atm}}$ for ${{\text{P}}_{{\text{C}}{{\text{l}}_{\text{2}}}}}$ and $2.22 \times {10^{ - 4}}{\text{ atm}}$ for ${{\text{P}}_{{\text{CO}}}}$ in equation (2).

$\begin{aligned}{{\text{P}}_{{\text{COC}}{{\text{l}}_2}}} &= \left( {1.49 \times {{10}^8}} \right)\left( {2.22 \times {{10}^{ - 4}}{\text{ atm}}} \right)\left( {2.22 \times {{10}^{ - 4}}{\text{ atm}}} \right) \\&= 7.343316{\text{ atm}} \\\end{aligned}$

Learn more:

Sort the solubility of gas will increase or decrease: . What is the pressure of the gas?: .

Answer details:

Grade: Senior School

Subject: Chemistry

Chapter: Chemical equilibrium

Keywords: Kp, CO, Cl2, COCl2, 7.343316 atm, chemical equilibrium, pressure, partial pressure, phosgene, PCl2, PCO, PCOCl2.

Answer from: Quest

the answer would be b i believe

Answer from: Quest

Answer : option c) heat is released during the process.explanation :

the enthalpy of formation of water is given as -285.8kj/mol, which states that the enthalpy of formation is negative.

negative enthalpy of formation indicates that the heat is released during the reaction process. the heat is released from reaction to the surroundings the enthalpy is expressed with a negative sign with the energy given out in the reaction process.

the formation of water takes place by giving out heat which is -285.8 kj/mol.

Another question on Chemistry

Chemistry, 22.06.2019 04:30

Both josef loschmidt and amedeo avogadro contributed to our understanding of basic molecular numbers, sizes, and reaction ratios. neither scientist discovered “avogadro’s number” in the form we use it today (6.02 x 10 23). still, there’s a controversy over the name. research the contributions from these two scientists and read about how avogadro’s number got its name. briefly state what you think this number should be called, providing key details of each scientist’s contributions to this concept and a solid rationale for your case in naming the number.

Answers: 2

Answer

Chemistry, 22.06.2019 11:00

What is the molar mass of a gas that has density of 2.054 g/l

Answers: 2

Answer

Chemistry, 22.06.2019 13:00

Lab reagent, hypothesis test.a reference solution used as a lab reagent is purported to have a concentration of 5 mg/dl. six samples are taken from this solution and the following concentrations are recorded: (5.32, 4.88, 5.10, 4.73, 5.15, 4.75) mg/dl.these six measurements are assumed to be an srs of all possible measurements from solution.they are also assumed to have a standard deviation of 0.2, a normal distributin, and a mean concentration equal to the true concentration of the solution.carry out a significance test to determine whether these six measurements provide reliable evidence that the true concentration of the solution is actually not 5 mg/dl.

Answers: 1

Answer

Chemistry, 22.06.2019 18:10

Consider the following reaction at equilibrium: c(s)+h2o(g)⇌co(g)+h2(g) predict whether the reaction will shift left, shift right, or remain unchanged upon each of the following disturbances. a) c is added to the reaction mixture. b) h2ois condensed and removed from the reaction mixture c) co is added to the reaction mixture d) h2 is removed from the reaction mixture.

Answers: 3

Answer

You know the right answer?

The kp for the reaction below is 1.49 × 108 at 100.0°c: co(g) + cl2(g) → cocl2(g) in an equilibrium...

Questions