ADD NOTE O QUESTION GUIDE EXIT TEST 16. Radio station A broadcasts a signal with a frequency of 98.7 MHz,
and radio station B broadcasts a signal with a frequency of 100.3 MHz.
What can be said about the relationship of signal A to signal B?

Signal A has a longer wavelength than signal B.

Explanation:

To know the the correct answer to the question given above, we shall determine the energy and the wavelength of both radio signals.

This is illustrated below:

1. Determination of the energy of both radio signals

i. Energy of signal A

Frequency (f) = 98.7 MHz = 98.7×10⁶ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =.?

E = hf

E = 6.63×10¯³⁴ × 98.7×10⁶

E = 6.54×10¯²⁶ J

ii. Energy of signal B

Frequency (f) = 100.3 MHz = 100.3×10⁶ Hz

Planck's constant (h) = 6.63×10¯³⁴ Js

Energy (E) =.?

E = hf

E = 6.63×10¯³⁴ × 100.3×10⁶

E = 6.65×10¯²⁶ J

2. Determination of the wavelength of both radio signals.

i. Wavelength of signal A:

Frequency (f) = 98.7 MHz = 98.7×10⁶ Hz

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 98.7×10⁶

Divide both side by 98.7×10⁶

λ = 3×10⁸ / 98.7×10⁶

λ = 3.04 m

ii. Wavelength of signal B

Frequency (f) = 100.3 MHz = 100.3×10⁶ Hz

Velocity (v) = 3×10⁸ m/s

Wavelength (λ) =?

v = λf

3×10⁸ = λ × 100.3×10⁶

Divide both side by 100.3×10⁶

λ = 3×10⁸ / 100.3×10⁶

λ = 2.99 m

The above calculation is summarised in the table below:

Signal >> Energy >>>>> Wavelength

A >>>>>> 6.54×10¯²⁶ >> 3.04

B >>>>>> 6.65×10¯²⁶ >> 2.99

From the above illustration,

1. Signal A has lesser energy than signal B.

2. Signal A has a longer wavelength than signal B.

hope this

explanation:

covalent bonds

consist of pairs of electrons shared by two atoms, and bind the atoms to fixed orientation and requre high energies to break them

ionic bonds

when two atoms differ considerably in their electronegativity, then one of the atoms will lose its electron to the other atom. this results in a positively charged ion(cation) and a negatively charged ion (anion)

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explanation:

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