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Chemistry, 16.10.2020 14:01 haileyvaldiviez5208

Un estudiante preparo 200 ml de solución de acetato de potasio (CH3COOH ; Masa molar = 98 g/mol ; Ka CH3COOH = 1,8 x 10-5), disolviendo 3,5 g de ácido la que denomino “Solución A”. Posteriormente preparo otra solución de menor concentración del mismo soluto que denomino “solución B” y para ello tomo un volumen de 5,5 ml de la solución A y agrego agua hasta 70 ml de solución. Señala el pH de de la solución A y B, y la concentración molar de CH3COO- en la solución B.

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Un estudiante preparo 200 ml de solución de acetato de potasio (CH3COOH ; Masa molar = 98 g/mol ; Ka...
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