A gas takes up a volume of 17 liters, has a pressure of 1748mmHg, and a temperature of 299K. If I raise the volume to 25 liters and lower the pressure to 1140mmHg, what is the new temperature of the gas?

answer: the enthalpy of the overall chemical reaction is +87.88 kj or +88 kj.

according to hess's law, the overall enthalpy of a reaction is the difference between the sum of enthalpy values of all the products and the sum of enthalpy values of all the reactants.

δh(reaction) = ∑nδh(products) - ∑nδh(reactants)

δh(reaction) = [δh +δh] - [δh]

δh(reaction) = [1(-287.02) + 1(0) ] - [1(-374.9)] kj = +87.88 kj

here, δh (pcl3) = -287.02 kj, δh(cl2) = 0, δh(pcl5) = -374.9 kj

therefore, enthalpy of the overall reaction is +87.88 kj or +88 kj.

i wish i could but this one is weird give me abc and i can solve it.

im doing test rn im going with 2 but ill give answer if itss wrong,   : )