A mixture of xenon and oxygen gas is compressed from a volume of to a volume of , while the pressure is held constant at . Calculate the work done on the gas mixture. Round your answer to significant digits, and be sure it has the correct sign (positive or negative).

Explanation:

Hello,

In this case, since the work at constant pressure is computed via:

For an initial volume of 99.0 L and a final one of 98.0 L, accounting for a compression process at a pressure of 69.0 atm, we obtain a negative work, meaning that work is done on the gas, according to the first law of thermodynamics:

However, the work in kJ with three significant figures because the initial data have all three significant figures, is:

Best regards.

"you start with 15.67 g mgco3-xh2o, when heated and all the water is removed, you are left with 7.58 g mgco3 only.

therefore, you had 15.67 - 7.58 = 8.09g h2o  

moles of each :

7.58g mgco3 = ? moles = 7.58g / 83.4g/mole = 0.09moles  

8 09g h2o = ? moles = 8.09g / 18g/mole = 0.44moles  

molar ratio between the two by dividing both numbers by the smallest number :

0.09 / 0.09 = 1  

0.44 / 0.09 = 4.8  

mgco3-5h2o"

aquifers are bounded above and below by impermeable rock. the driving force of groundwater movement in confined aquifers is pressure, rather than gravity.