How many milliliters of 10.7 M perchloric acid solution should be used to prepare 5.50 L of 0.200 M

102.8 mL.

Explanation:

From the question given above, the following data were obtained:

Molarity of stock solution (M1) = 10.7 M

Molarity of diluted solution (M2) = 0.2 M

Volume of diluted solution (V2) = 5.5 L

Volume of stock solution needed (V1) =.?

The volume of the stock solution needed can be obtained by using the following formula:

M1V1 = M2V2

10.7 × V2 = 0.2 × 5.5

10.7 × V2 = 1.1

Divide both side by 10.7

V2 = 1.1 / 10.7

V2 = 0.1028 L

Finally, we shall convert 0.1028 L to millilitres (mL) in order to obtain the desired result. This can be obtained as follow:

1 L = 1000 mL

Therefore,

0.1028 L = 0.1028 L × 1000 mL / 1 L

0.1028 L = 102.8 mL

Therefore, 0.1028 L is equivalent to 102.8 mL.

Thus, 102.8 mL of the stock solution (i.e perchloric acid) is needed.

trigonal pyramidal

tetrahedral

trigonal planar

bent

that's what i got you can count the number of atoms