Which is the stronger acid in each of the following pairs?

I. HClO2 or HClO3

II. H2S or H2Se

III. H3AsO4 or H2SeO4

a.
I. HClO2 II. H2Se III. H3AsO4
b.
I. HClO3 II. H2Se III. H2SeO4
c.
I. HClO3 II. H2Se III. H3AsO4
d.
I. HClO2 II. H2S III. H2SeO4
e.
I. HClO3 II. H2S III. H2SeO4

the answer is b & c i believe : )

2b2t

explanation:

2b2t

"record the time to complete a chemical reaction" would most likely be part of a lab procedure.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied