A Cu/Cu2 concentration cell has a voltage of 0.22 V at 25 o C. The concentration of Cu2 in one of the half-cells is 1.5 x 10-3 M. What is the concentration of Cu2 in the other half-cell

The concentration is    

Explanation:

From the question we are told that

    The voltage of the cell is  

Generally the reaction at the cathode is  

  the half cell voltage is  V_c =  0.337 V

Generally the reaction at the anode is    

     the half cell voltage is  V_a = -0.337 V

Gnerally the reaction of the cell is  

At initial the voltage is  V  =  0 V

Generally the voltage of the cell at 25°C is  

Here n is number of  of electron and it is 2

So from the question we are told that one cell has a concentration 1.5 x 10-3 M

Let assume it is  

So

=>    

=>  

=>    

=>    

Taking the antilog

=>        

=>      

2h2o2--> 2h2o + o2

this reaction is of the spontaneous decomposition of hydrogen peroxide down into water and oxygen.

add 2 molecules of hydrogen peroxide and 2 molecules of water. since oxygen is naturally diatomic, the total number of atoms of each element is now the same on both sides of the equation so it is balanced.

this may not be entirely correct but let me know.