How many atoms are in 75.4 moles of Copper?

No = Avagardro's number = 6.02 x 10^23

No.of atoms = no.of moles x No x atomicity

= 75.4 x 6.02 10^23 x 1

= 453.908 x 10^23 atoms .

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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