The volume of a gas is 590 mL at 384 kPa pressure. What will the volume be when the pressure is changed to 546 kPa, assuming the temperature remains constant?

Explanation:

To find the volume when the pressure is changed to 546 kPa , we use the formula for Boyle's law which is

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

We have

We have the final answer as

Hope this helps you

you need to take a look at the periodic system in order to sort these elements into pairs that would most likely exhibit similar chemical properties. first, you need to find elements that are found in the same group (groups are vertical in the periodic system), and then to see whether they have the same valence number. if they meet these criteria, they will have similar properties.

the first pair: ne (neon) and kr (krypton), are noble gases found in group 8

the second pair: li (lithium) and k (potassium), found in group 1

the third pair: s (sulfur) and te (tellurium), found in group 6