You are given a bottle of impure CoSO4 7H2O which is thought to be 74.4% by weight CoSO4 7H2O. You propose to run your own analysis to find out. What weight of sample should you take to get 0.345 g of BaSO4?

Explanation:

Hello.

In this case, considering a representative reaction by which BaSO4 is yielded via CoSO4, for instance:

Since it is desired to obtain 0.345 g of BaSO4 (molar mass = 233.38 g/mol), we can compute the theoretical mass of CoSO4·7H20 (molar mass = 281 g/mol) via the following stoichiometric procedure:

Next, given the percent purity of the cobalt (II) sulfate heptahydrate, we can compute the mass of the whole sample as shown below:

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