A ball initially at rest is dropped from a window sill 14.2 m off the ground. Find the velocity of the ball the moment it hits the ground. Round your answer to 2 decimals places.

16.68 m/s

Explanation:

The following data were obtained from the question:

Height (h) = 14.2 m

Initial Velocity (u) = 0 m/s

Final velocity (v) =?

Thus, the velocity (v) with which the ball hit the ground can be obtained as follow:

v² = u² + 2gh

NOTE: the acceleration due to gravity (g) = 9.8 m/s²

v² = u² + 2gh

v² = 0² + 2 × 9.8 × 14.2

v² = 0 + 278.32

v² = 278.32

Take the square root of both side

v = √278.32

v = 16.68 m/s

Therefore, the velocity with which the ball hit the ground is 16.68 m/s

the right answer is c i just did the question.