What is the complete ionic equation for NaOH(aq) + HCl(aq) → H2O() + NaCl(aq)? O A. Na+ + OH + H+ + Cl → H2O + Na+ + CH O

B. OH + H* → H2O

C. Na+ + Cl → NaCl

D. Na+ + OH + H+ + Cl + H+ + OH+ + Na+ + CH-

bean

Explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

am i too late?

explanation: