Calculate the nuclear binding energy per nucleon for cobalt-59, the only stable isotope of cobalt. The mass of cobalt-59 is 58.933198 amu. (The mass of 11H is 1.00783 amu, and the mass of a neutron is 1.00866 amu.)

8.54 * 10^15 J

Explanation:

For Co-59

Protons- 27

Neutrons- 32

total calculated mass of protons = 27 * 1.00783 amu = 27.211 amu

total calculated mass of neutrons = 32 * 1.00866 amu =37.320 amu

Total calculated mass of nucleons = 27.211 amu + 37.320 amu = 64.531 amu

Mass defect = 64.531 amu - 58.933198 amu = 5.5978 amu

Binding energy = E=(Δm)c^2

Δm= mass defect

c=  speed of light

E=  5.5978 amu (3.0 *10^8)^2

E= 5.03 * 10^17 J

Binding energy per nucleon = Binding energy/ total number of nucleons

= 5.03 * 10^17 J/ 59 = 8.54 * 10^15 J

the answer to this question is 3.

here is table 2-2:

country

percent of eligible voters that voted

rank

united states

44.9%

138

canada

60.1%

107

costa rica

84.6%

14

hungary

66.9%

82

japan

57.0%

118

egypt

27.7%

159

south africa

85.5%

10

ans is no, the data set cannot be plotted as a single circle graph