Station 9: Iodine g I2 Perform the calculations in the space between each lettered problem. Enter the answer with correct significant figures and units on the line provided.

a) Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = 4.50 * 10²² molecules

Note: The complete question is found in the attachment below.

Explanation:

a. Number of moles of iodine molecules in 19.0 g of I₂

Molar mass of iodine molecule = 2 * 127 g/mol = 254g/mol

Number of moles = mass / molar mass

Number of moles = 19.0 g / 254 g/mol

Moles of iodine molecules = 0.0748 moles of Iodine molecules

b) Number of moles of iodine atoms

I mole of iodine molecules contains 2 moles of iodine atoms

Therefore, 0.0748 moles of iodine molecules will contain 2 * 0.0748 moles of iodine atoms

Moles of iodine atoms = 0.150 moles of iodine atoms

c) Number of iodine atoms = number of moles of iodine atoms * 6.02 * 10²³

Number of iodine atoms = 0.150 * 6.02 * 10²³

Number of iodine atoms = 9.03 * 10²² atoms

d) Number of iodine molecules = number of moles of iodine molecules * 6.02 * 10²³

Number of iodine molecules = 0.0748 * 6.02 * 10²³

Number of iodine molecules = 4.50 * 10²² molecules

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

2b2t

explanation:

2b2t