The combustion of ethane (C2H6) produces carbon dioxide and steam. 2C2H6(g)+7O2(g)⟶4CO2(g)+6H2O(g) How many moles of CO2 are produced when 5.90 mol of ethane is burned in an excess of oxygen?

11.8 moles of CO2.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

2C2H6 + 7O2 —> 4CO2 + 6H2O

From the balanced equation above,

2 moles of C2H6 reacted with 7 moles of O2 to produce 4 moles of CO2 and 6 moles of H2O.

Thus, we can obtain the number of moles of CO2 produced when 5.9 moles of C2H6 is burned in excess O2 as follow:

From the balanced equation above,

2 moles of C2H6 reacted to produce 4 moles of CO2.

Therefore, 5.9 moles of C2H6 will react to produce = (5.9 × 4)/2 = 11.8 moles of CO2.

Thus, 11.8 moles of CO2 were obtained from the reaction.

answer: the figure is attached herewith.

step-by-step explanation:   we are given to sketch a unit circle and label the terminal points corresponding to

in the attached figure, we have drawn a unit circle, with centre at o(0,0) and radius 1 unit. we have labelled the points a, b, c, d and e corresponding to the angles below

∠aox = 60°,

∠box = 120°,

∠cox = 180°,

∠dox = 240°,

∠eox = 300°.

and the coordinates are a(0.5,1), b(-0.5,1), c(-1,0), d(-0.5,-1) and e(0.5,-1).

thus, the answer is complete.