The observed rotation of a solution of 1.3 g of a compound in 10 mL of water is 11 degrees. If the pathlength is 10 cm, what is the specific rotation of the compound

The specific rotation of the compound is +84.6°.

Explanation:

The specific rotation of the compound can be found using the following equation:

Where:

α: is the observed rotation of a solution = +11°

c: is the concentration

l: is the pathlength = 10 cm = 1.0 dm        

Therefore, the specific rotation of the compound is +84.6°

I hope it helps you!          

im pretty sure its b

b) nuclear ive learned that in a pedtrodic table