PLEASE HELP ME ON THIS QUESTION ASAP The ∆Hfusion for water is 334 J/g.
After 19.0 kJ of energy is added to a block of ice initially at 0°C, how many grams melted?

56.9kg

Explanation:

Given parameters:

∆Hfusion = 334J/g

Amount of energy  = 19kJ or 19 x 10³J

Initial temperature  = 0°C

Unknown:

Quantity of ice melted =  ?

Solution:

This process is a simple phase change from ice to water at the same temperature.

    H  = mL

   m is the mass of the ice

    L is the heat of fusion

   H is the amount of supplied heat

Insert the parameters and solve;

     19 x 10³ = m x 334

          m =   = 56.9kg

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