Chemistry, 23.10.2020 03:01 braines2003
The rate constant for the reaction below was determined to be 3.241×10-5 s–1 at 800 K. The activation energy of the reaction is 255 kJ/mol. What would be the value of the rate constant at 9.50×102 K?
Answers: 1
![k_2=k_1exp[-\frac{Ea}{R}(\frac{1}{T_2}-\frac{1}{T_1} )]](/tpl/images/0834/1791/1a893.png)
![k_2=3.241x10^{-5}s^{-1}exp[-\frac{255000}{8.314}(\frac{1}{950}-\frac{1}{800} )]\\\\k_2=1.379x10^{-2}s^{-1}](/tpl/images/0834/1791/1944c.png)
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The rate constant for the reaction below was determined to be 3.241×10-5 s–1 at 800 K. The activatio...
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