The catalytic destruction of ozone occurs via a two-step mechanism, where X can be any of several species:

Kindly check the explanation section.

Explanation:

Just like it is given or said in the question/problem above we have that the catalytic destruction of ozone occurs via a two-step mechanism. The two step mechanism in which one of the step is fast and the other step is slow is given in the reaction below;

=> X + O3 > XO + O2.

This the slow step.

The rate law for the slow step = k(slow) [X][O3].

=> XO + O > X + O2.

This is the fast step.

The rate law for the fast step = k(fast) [XO][O].

Therefore, the overall reaction involves the cancellation of the two XOs present in the first and second step respectively and cancellation of Xs present In the first and second step respectively.

Therefore, the overall reaction gives;

O3 + O > 2O2.

Note that the XO stands for the intermediate while the X stand for the catalyst.

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the electronic configuration of an atom with eight electrons is 1s²2s²2p⁴. the orbital diagrams are shown in the figure.

as per the hunds rule:

1. electrons tend to avoid being in the same orbital as per as practicable.

2. electrons in different orbitals of the same energy will have their spin parallel.

this can be illustrated from the multiplicity of the orbitals of the atom. as there are four electrons in the p orbital and p orbital has 3 sub-shells. the electrons can be fed in different ways as shown in the figure but the correct orbital diagram will be as per the hunds rule.