calculate the mass percent composition of a mixture that contains 26 grams of copper and 79 grams of silver

Explanation:

Mass percentage composition of copper and silver in the mixture will be calculated differently, sum of which must be equal to 100 to show the calculation is right.

To determine the percentage, one must first add the sum of the two masses together 26 + 79 = 105 g

If the mass of copper is 26 g, % by mass of copper = 26/105 × 100

mass percent of copper = 24.76%

If the mass of silver is 79 g, % by mass of silver = 79/105 × 100

mass percent of silver = 75.24%

NOTE: To show the calculation is right 24.76 + 75.24 = 100

idk i’m struggling too

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml