A block of lead has dimensions 4.5 cm by 5.2 cm by 6.0 cm. The block weighs 1587 g. From this information, calculate the density of lead.

d = 11.3 g/cm³

Explanation:

Given data:

Dimensions of lead block = 4.5 cm,5.2 cm, 6.0 cm

Weight of block = 1587 g

Density of lead block = ?

Solution:

Density:

Density is equal to the mass of substance divided by its volume.

Units:

SI unit of density is Kg/m3.

Other units are given below,

g/cm3, g/mL , kg/L

Formula:

D=m/v

D= density

m=mass

V=volume

Volume = 4.5 cm×5.2 cm×6.0 cm

Volume = 140.4 cm³

d = 1587 g/ 140.4 cm³

d = 11.3 g/cm³

lol idk man i guess u gotta ask bill nye the science guy

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :