6.03g of gas has a volume of 1.00 L at STP determine the g-molar mass of the gas.

Molar mass = 135.2 g/mol

Explanation:

Given data;

Mass of gas = 6.03 g

Volume of gas = 1.00L

Temperature = standard = 273 K

Pressure = Standard = 1 atm

Molar mass of gas = ?

Solution:

First of all we will calculate the number of moles of gas.

Formula

PV = nRT

1 atm ×  1.00L = n × 0.0821 atm.L/k.mol × 273 K

1.00 atm.L = n × 22.414  atm.L/mol

n = 1.00 atm.L/22.41  atm.L/mol

n = 0.0446 mol

Molar mass:

Molar mass = mass/number of moles

Molar mass = 6.03 g/0.0446 mol

Molar mass = 135.2 g/mol

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