What is the mass in grams of 381 mL of ethylene glycol?
Has a density of 1.11 grams/cm^3

Explanation:

The mass of a substance when given the density and volume can be found by using the formula

From the question

volume = 381 mL = 381 cm³

density = 1.11 g/cm³

So we have

mass = 1.11 × 381

We have the final answer as

Hope this helps you

yea hi

explanation:

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g