Dadas las siguientes ecuaciones y valores de ∆H° determine el calor de reacción (kJ) a 298 K para la reacción: 3 Fe2O3 (s) → 2 Fe3O4 (s) + 1/2 O2 (g)
Si:
2 Fe (s) + 3/2 O2 (g) → Fe2O3 (s) ∆H°= -823,41 kJ
3 Fe (s) + 2 O2 (g) → Fe3O4 (s) ∆H°= -1120,48 kJ

in the given question, the partial pressure is calculated by using the ideal gas equation, that is, pv = nrt

here, p is pressure, v is volume = 25 l, n is number of moles = 0.0104 moles, r is gas constant = -0.0821 l.atm / mol.k

t is temperature = 273 k

p = nrt / v

p = (0.0104 mol × 0.0821 l.atm / mol.k × 273 k) / 25 l

= 0.0093 atm

you need to stop taking that class