Question 2 (4 points) When sodium chloride dissolves in water, the partially negative end of the water molecule is attracted to the negative choride ion and the
partially positive end of the water molecule is attracted to the positive sodium ion. This type of intermolecular force is best described as:
a
b
London force
dipole-dipole force
dipole-ion force
Van der Waals force
Od

given:

mass of na = 115 g

excess cl2

to determine:

mass of nacl produced

explanation:

given reaction is-

2na(s) + cl2(g) → 2nacl(s)

since cl2 is in excess, na will be the limiting reagent

as per the reaction stoichiometry na: nacl = 1: 1

i.e. moles of na reacted = moles of nacl formed

now, # moles of na = mass of na/atomic mass

                                  = 115 g/23 g.mol-1 = 5 moles

therefore, moles of nacl = 5

molar mass of nacl = 58 g/mol

mass of nacl = 5 moles * 58 g.mol-1 = 290 g

ans: amount of nacl produced = 290 g

the electron configuration that you gave me has 16 electrons ergo it has 16 protons ergo it is the element sulfur.