How much volume of a 6.00 M solution of HClO4 is needed to prepare 4.00 L of 0.250 M HClO4 In hurry please

We are given:

m1 = 6 M                   v1 = x L

m2 = 0.250 M          v2 = 4 L

Using the dilution equation:

m1*v1 = m2*v2

(6)*(x) = (0.250)(4)

6x = 1

x = 1 / 6

Hence, 1/6 Litres (0.167 L) of 6M solution is required in order to make 4 litres of 0.250 M solution of HClO₄

explanation:

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