In a titration, what volume of 0.50 M HNO3 is required to completely react with 16.0 mL of 1.250 M KOH according to the equation HNO3(aq) KOH(aq) -> KNO3(aq) H2O(l)

Given :

A reaction , HNO3(aq) + KOH(aq) -> KNO3(aq) +  H2O(l)

To Find :

Volume of 0.50 M HNO3 is required to completely react with 16.0 mL of 1.250 M KOH .

Solution :

From the equation we can see that 1 mol of HNO3 react with 1 mol of KOH.

So,

Therefore, volume of HNO3 required is 40 ml.

Hence, this is the required solution.

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is there any options? maybe im just not seeing them but i need the options to

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