A mixture of krypton and argon gas is compressed from a volume of 53.0 L to a volume of 47.0 L , while the pressure is held constant at . Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

1.28 × 10⁴ J

Explanation:

A mixture of krypton and argon gas is compressed from a volume of 53.0 L to a volume of 47.0 L, while the pressure is held constant at 21.0 atm. Calculate the work done on the gas mixture. Be sure your answer has the correct sign (positive or negative) and the correct number of significant digits.

Step 1: Given data

Initial volume of the gaseous mixture: 53.0 LFinal volume of the gaseous mixture: 47.0 LPressure (P): 21.0 atm

Step 2: Calculate the work done on the gas mixture (W).

We will use the following expression.

W = - P × ΔV

W = - 21.0 atm × (47.0 L - 53.0 L)

W = 126 atm.L

Step 3: Convert "W" to Joule

We will use the conversion factor 1 atm.L = 101.325 J.

126 atm.L × (101.325 J/1 atm.L) = 1.28 × 10⁴ J

We first assume that this gas is an ideal gas where it follows the ideal gas equation. the said equation is expressed as: pv = nrt. from this equation, we can predict the changes in the pressure, volume and temperature. if the volume and the temperature of this gas is doubled, then the pressure still stays the same.

Hcn is the correct answer leave a good rate and .