The ethyl alcohol in "gasohol" burns to form CO 2 and H 2O. If the combustion reaction consumes 6.645 moles of C 2H 5OH reacting with excess O 2, how many grams of H 2O are formed

359.3 g

Explanation:

Step 1: Write the balanced combustion reaction

C₂H₅OH + 3 O₂ ⇒ 2 CO₂ + 3 H₂O

Step 2: Calculate the moles of water formed from 6.645 moles of ethyl alcohol

The molar ratio of C₂H₅OH to H₂O is 1:3.

6.645 mol C₂H₅OH × (3 mol H₂O/1 mol C₂H₅OH) = 19.94 mol H₂O

Step 3: Calculate the mass corresponding to 19.94 moles of H₂O

The molar mass of H₂O is 18.02 g/mol.

19.94 mol × 18.02 g/mol = 359.3 g

answer: the rate of diffusion increases with increase in temperature.

increase in temperature, increases the molecular/particles speed (kinetic energy. diffusion means movement of particles through the material.

generally, the heavier the particle the more it interacts with the environment and more the temperature matters. so higher temperature results in higher diffusion.