A solution of H2SO4(aq) with a molality of 3.22 m has a density of 1.183 g/mL. What is the molar concentration of this solution

Explanation:

H₂SO₄

density of solution = 1.183 g / mL

= 1183 g / L

1.183 kg / L

volume of 1 kg of solution = 1 / 1.183 L

= .8453 L

molality of H₂SO₄ = 3.22 m

3.22 moles in 1 kg of solvent

3.22 moles in .8453 L of solution

[ volume of solute is negligible ]

molarity of solution

= 3.22 / .8453 M

= 3.81 M

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