Calculate the mass defect for 239U239U, which has a mass of 239.05429 amuamu . (The mass of 11H11H is 1.00783 amuamu, and the mass of a neutron is 1.00866 amuamu .)

The mass defect for U-239 is 1.93909 amu.

Explanation:

The mass defect can be calculated using the following equation:

Where:

: is the proton mass = 1.00783 amu

: is the neutron mass = 1.00866 amu        

M: is the mass of U-239 = 239.05429 amu

Z: is the number of protons = 92

N: is the number of neutrons = A - Z

A: is the atomic mass number = 239

Therefore, the mass defect for U-239 is 1.93909 amu.

I hope it helps you!                                                        

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied