2: NSCI pls
We mix 51 grams of oxygen gas with
21 grams of argon gas in a volume of 1593 mL
at –14°C. What will be the final pressure of
the gas mixture?
Answer in units of atm.

answer : third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

explanation :

let us write down the given equations

equation 1 :

equation 2 :

equation 3 :

let us use hess's law to find out which 2 equations can be added to get the third equation.

let us reverse equation 2 and multiply it by 2. the new equation that we get is,

equation 4 :

let us add equation 1 & 4

the above equation is similar to equation 3 but has different value for dhrxn.

therefore third trial had the contaminated sample and the correct value for dhrxn should be 1000 kj/mol

the correct answer would be b) volume versus temperature, because they are also directly proportional.